is it possible to hide the raw dict while printing dict as Tree

[asbisen]

Using the example

data = Dict(
    "a" => 1,
    "b" => Int64,
    "deep" => Dict(
            "x" => 1,
            "y" => :x
    ),
)

print(Tree(data))

The content is printed as

Dict("deep" => Dict("x" => 1, "y" => :x),
  "b" => Int64, "a" => 1)
  ├─ deep ⇒ Dict("x" => 1, "y" => :x)
  │         ├─ x ⇒ 1
  │         └─ y ⇒ x
  ├─ b ⇒ Int64
  └─ a ⇒ 1

Is it possible to just print the tree part hiding the raw output (something like this)

data
  ├─ deep ⇒ Dict()
  │         ├─ x ⇒ 1
  │         └─ y ⇒ x
  ├─ b ⇒ Int64
  └─ a ⇒ 1

[FedeClaudi]

yep:

using Term
using Term.Trees

data = Dict(
    "a" => 1,
    "b" => Int64,
    "deep" => Dict(
            "x" => 1,
            "y" => :x
    ),
)

print(Tree(data; title="data"))

data                                 
  ├─ deep ⇒ Dict("x" => 1, "y" => :x)
  │         ├─ x ⇒ 1                 
  │         └─ y ⇒ x                 
  ├─ b ⇒ Int64                       
  └─ a ⇒ 1                           
          

That removes the first "raw" output replacing it with a title. For the inner deep ⇒ Dict() it will print the whole Dict there unfortunately. You can always pass your print_node function to Tree to achieve exactly what you want it to do though.

[FedeClaudi]

For example:

function pn(io, node; kw...)
    if node isa AbstractDict
        print(io, string(typeof(node)))
    else
        print(io, node)
    end

end

print(Tree(data; title="data", printkeys=true, print_node_function=pn))

Dict                
  ├─ deep ⇒ Dict    
  │         ├─ x ⇒ 1
  │         └─ y ⇒ x
  ├─ b ⇒ Int64      
  └─ a ⇒ 1