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julia> spzeros(2) + [1.4, 3] 2-element SparseVector{Float64, Int64} with 2 stored entries: ⋮ [2] = 3.0 julia> spzeros(2,2) + [1.4 3 0 2] 2×2 Matrix{Float64}: 1.4 3.0 0.0 2.0
The matrix behavior seems to be the most sensible, assuming that adding a dense and a sparse will yield something sparse seems very risky
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Agree. Having a dense result is the sensible- since one of the inputs was already dense.
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The matrix behavior seems to be the most sensible, assuming that adding a dense and a sparse will yield something sparse seems very risky
The text was updated successfully, but these errors were encountered: