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deleteDuplicates.py
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deleteDuplicates.py
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# Author: Yu Zhou
# 83. Remove Duplicates from Sorted List
# Given a sorted linked list, delete all duplicates such that each element appear only once.
#
# For example,
# Given 1->1->2, return 1->2.
# Given 1->1->2->3->3, return 1->2->3.
# 思路,不需要删除这个Node,只需要将Pointer指向之后的一个Node就行
# 中间有个容易出错的就是,不要每次While循环,自动位移当前的Pointer
# 在比对完当前Node和后面的所有Node直到没有重复的时候
# 再 cur = cur.next
# ****************
# Final Solution *
# ****************
class Solution(object):
def deleteDuplicates(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
cur = head
while cur and cur.next:
if cur.val == cur.next.val:
cur.next = cur.next.next
else:
cur = cur.next
return head
# ***************************************
# The following code is an fail attempt *
# ***************************************
class Solution(object):
def deleteDuplicates(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
cur = head
while cur and cur.next:
if cur.val == cur.next.val:
cur.next = cur.next.next
#问题出在这里
#cur不应该在每次比对以后直接位移,应该等没有
#duplicate以后再位移,所以这里要加Else
#不加的后果是,底下之中corner case会失败: [1,1,1]
cur = cur.next
return head