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6ZigZagConversion.swift
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6ZigZagConversion.swift
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/*
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string s, int numRows);
Examples:
Input: s = "PAYPALISHIRING", numRows = 3
Output: "PAHNAPLSIIGYIR"
Input: s = "PAYPALISHIRING", numRows = 4
Output: "PINALSIGYAHRPI"
Explanation:
P I N
A L S I G
Y A H R
P I
Input: s = "A", numRows = 1
Output: "A"
*/
class Solution {
func convert(_ s: String, _ numRows: Int) -> String {
guard numRows > 1 else { return s }
var stringedNumRows = Array(repeating: "", count: numRows)
var currentRow = 0
var shouldIncrease = false
for char in s {
stringedNumRows[currentRow] += String(char)
if currentRow == 0 || currentRow == numRows - 1 {
shouldIncrease = !shouldIncrease
}
currentRow = shouldIncrease ? currentRow + 1 : currentRow - 1
}
return stringedNumRows.joined()
}
}