008.vl

$ Project Euler problem #8 $
$ Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product? $

$ load 1000 digit number as string $
i7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450;
/           $ explode into individual characters into 'a $
0v2(]p)     $ initialise 'b and 'c to 0 $
'bY`a       $ set starting position for sum $
1v          $ init value to 1 $
13(Vy=*1})  $ multiply together next 13 numbers $
'cY>jp      $ save to 'c if bigger than previous 'c $
'ba987<j4k  $ increase starting position by one, exiting if it is greater than 987 $
'cyl        $ print out max found $