Integrals.jl is an instantiation of the SciML common IntegralProblem
interface for the common numerical integration packages of Julia, including
both those based upon quadrature as well as Monte-Carlo approaches. By using
Integrals.jl, you get a single predictable interface where many of the
arguments are standardized throughout the various integrator libraries. This
can be useful for benchmarking or for library implementations, since libraries
which internally use a quadrature can easily accept a integration method as an
argument.
For information on using the package, see the stable documentation. Use the in-development documentation for the version of the documentation, which contains the unreleased features.
To perform one-dimensional quadrature, we can simply construct an IntegralProblem
. The code below evaluates IntegralProblem
.
using Integrals
f(x, p) = sin(x * p)
p = 1.7
domain = (-2, 5) # (lb, ub)
prob = IntegralProblem(f, domain, p)
sol = solve(prob, QuadGKJL())
For basic multidimensional quadrature we can construct and solve a IntegralProblem
. Since we are using no arguments p
in this example, we omit the third argument of IntegralProblem
from above. The lower and upper bounds are now passed as vectors, with the i
th elements of
the bounds giving the interval of integration for x[i]
.
using Integrals
f(x, p) = sum(sin.(x))
domain = (ones(2), 3ones(2)) # (lb, ub)
prob = IntegralProblem(f, domain)
sol = solve(prob, HCubatureJL(), reltol = 1e-3, abstol = 1e-3)
If we would like to parallelize the computation, we can use the batch interface to compute multiple points at once. For example, here we do allocation-free multithreading with Cubature.jl:
using Integrals, Cubature, Base.Threads
function f(dx, x, p)
Threads.@threads for i in 1:size(x, 2)
dx[i] = sum(sin, @view(x[:, i]))
end
end
domain = (ones(2), 3ones(2)) # (lb, ub)
prob = IntegralProblem(BatchIntegralFunction(f, zeros(0)), domain)
sol = solve(prob, CubatureJLh(), reltol = 1e-3, abstol = 1e-3)
If we would like to compare the results against Cuba.jl's Cuhre
method, then
the change is a one-argument change:
using Cuba
sol = solve(prob, CubaCuhre(), reltol = 1e-3, abstol = 1e-3)