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dict.go
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dict.go
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package sprig
func get(d map[string]interface{}, key string) interface{} {
if val, ok := d[key]; ok {
return val
}
return ""
}
func set(d map[string]interface{}, key string, value interface{}) map[string]interface{} {
d[key] = value
return d
}
func unset(d map[string]interface{}, key string) map[string]interface{} {
delete(d, key)
return d
}
func hasKey(d map[string]interface{}, key string) bool {
_, ok := d[key]
return ok
}
func pluck(key string, d ...map[string]interface{}) []interface{} {
res := []interface{}{}
for _, dict := range d {
if val, ok := dict[key]; ok {
res = append(res, val)
}
}
return res
}
func keys(dicts ...map[string]interface{}) []string {
k := []string{}
for _, dict := range dicts {
for key := range dict {
k = append(k, key)
}
}
return k
}
func pick(dict map[string]interface{}, keys ...string) map[string]interface{} {
res := map[string]interface{}{}
for _, k := range keys {
if v, ok := dict[k]; ok {
res[k] = v
}
}
return res
}
func omit(dict map[string]interface{}, keys ...string) map[string]interface{} {
res := map[string]interface{}{}
omit := make(map[string]bool, len(keys))
for _, k := range keys {
omit[k] = true
}
for k, v := range dict {
if _, ok := omit[k]; !ok {
res[k] = v
}
}
return res
}
func dict(v ...interface{}) map[string]interface{} {
dict := map[string]interface{}{}
lenv := len(v)
for i := 0; i < lenv; i += 2 {
key := strval(v[i])
if i+1 >= lenv {
dict[key] = ""
continue
}
dict[key] = v[i+1]
}
return dict
}
func values(dict map[string]interface{}) []interface{} {
values := []interface{}{}
for _, value := range dict {
values = append(values, value)
}
return values
}
func dig(ps ...interface{}) (interface{}, error) {
if len(ps) < 3 {
panic("dig needs at least three arguments")
}
dict := ps[len(ps)-1].(map[string]interface{})
def := ps[len(ps)-2]
ks := make([]string, len(ps)-2)
for i := 0; i < len(ks); i++ {
ks[i] = ps[i].(string)
}
return digFromDict(dict, def, ks)
}
func digFromDict(dict map[string]interface{}, d interface{}, ks []string) (interface{}, error) {
k, ns := ks[0], ks[1:len(ks)]
step, has := dict[k]
if !has {
return d, nil
}
if len(ns) == 0 {
return step, nil
}
return digFromDict(step.(map[string]interface{}), d, ns)
}