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_994.java
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_994.java
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package com.fishercoder.solutions;
import java.util.LinkedList;
import java.util.Queue;
/**
* 994. Rotting Oranges
*
* In a given grid, each cell can have one of three values:
*
* the value 0 representing an empty cell;
* the value 1 representing a fresh orange;
* the value 2 representing a rotten orange.
*
* Every minute, any fresh orange that is adjacent (4-directionally) to a
* rotten orange becomes rotten.
*
* Return the minimum number of minutes that must elapse until no cell has a fresh orange.
* If this is impossible, return -1 instead.
*
* Example 1:
* Input: [[2,1,1],[1,1,0],[0,1,1]]
* Output: 4
*
* Example 2:
* Input: [[2,1,1],[0,1,1],[1,0,1]]
* Output: -1
* Explanation: The orange in the bottom left corner (row 2, column 0) is never rotten, because rotting only happens 4-directionally.
*
* Example 3:
* Input: [[0,2]]
* Output: 0
* Explanation: Since there are already no fresh oranges at minute 0, the answer is just 0.
*
* Note:
*
* 1 <= grid.length <= 10
* 1 <= grid[0].length <= 10
* grid[i][j] is only 0, 1, or 2.
*/
public class _994 {
public static class Solution1 {
int[] directions = new int[] {0, 1, 0, -1, 0};
public int orangesRotting(int[][] grid) {
Queue<int[]> rottens = new LinkedList<>();
for (int i = 0; i < grid.length; i++) {
for (int j = 0; j < grid[0].length; j++) {
if (grid[i][j] == 2) {
rottens.add(new int[] {i, j});
}
}
}
int times = 0;
while (!rottens.isEmpty()) {
int size = rottens.size();
boolean counted = false;
for (int k = 0; k < size; k++) {
int[] rotten = rottens.poll();
for (int i = 0; i < 4; i++) {
int x = rotten[0] + directions[i];
int y = rotten[1] + directions[i + 1];
if (x >= 0 && x < grid.length && y >= 0 && y < grid[0].length && grid[x][y] == 1) {
grid[x][y] = 2;
if (!counted) {
times++;
}
counted = true;
rottens.add(new int[] {x, y});
}
}
}
}
for (int i = 0; i < grid.length; i++) {
for (int j = 0; j < grid[0].length; j++) {
if (grid[i][j] == 1) {
return -1;
}
}
}
return times;
}
}
}