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01_pairs-violating-the-bst-property.java
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01_pairs-violating-the-bst-property.java
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// april2024/01_pairs-violating-the-bst-property.java
/**
* Date : 01-Apr-24
* Repo : https://github.com/ankitsamaddar/
*
* Problem : Pairs violating the BST property
* Difficulty: 🟡Medium
*
* GeeksforGeeks : https://www.geeksforgeeks.org/problems/pairs-violating-bst-property--212515/1
*/
import java.io.*;
import java.util.*;
/*
Definition for Binary Tree Node
class Node
{
int data;
Node left;
Node right;
Node(int data)
{
this.data = data;
left = null;
right = null;
}
}
*/
class Solution {
public int pairsViolatingBST(int n, Node root) {
int count = 0;
ArrayList<Integer> inOrder = new ArrayList<>();
// Do in orderTraversal
// left -> root -> right
Stack<Node> st = new Stack<>();
while(root!=null || st.size()!=0) {
// iterate to the leftmost node
while(root != null){
st.push(root);
root = root.left;
}
// visit the leftmost node
// it is now the top of the stack
root = st.pop();
// save the left mode node data
inOrder.add(root.data);
// visit right node
root = root.right;
}
// In BST every node, strictly greater than left subtree, and strictly less than right subtree
// check each pair of nodes
for(int i=0;i<inOrder.size();i++) {
for(int j=i+1;j<inOrder.size();j++) {
// if any previous left node was greater than current node
// increment count
if(inOrder.get(i)>=inOrder.get(j)) {
count++;
}
}
}
// Total violations
return count;
}
}
//{ Driver Code Starts
class Node {
int data;
Node left;
Node right;
Node(int data) {
this.data = data;
left = null;
right = null;
}
public static Node buildTree(String str) {
// Corner Case
if (str.length() == 0 || str.charAt(0) == 'N') return null;
// Creating array of Strings from input
// String after spliting by space
String ip[] = str.split(" ");
// Create the root of the tree
Node root = new Node(Integer.parseInt(ip[0]));
// Push the root to the queue
Queue<Node> queue = new LinkedList<>();
queue.add(root);
// Starting from the second element
int i = 1;
while (queue.size() > 0 && i < ip.length) {
// Get and remove the front of the queue
Node currNode = queue.peek();
queue.remove();
// Get the current node's value from the string
String currVal = ip[i];
// If the left child is not null
if (!currVal.equals("N")) {
// Create the left child for the current node
currNode.left = new Node(Integer.parseInt(currVal));
// Push it to the queue
queue.add(currNode.left);
}
// For the right child
i++;
if (i >= ip.length) break;
currVal = ip[i];
// If the right child is not null
if (!currVal.equals("N")) {
// Create the right child for the current node
currNode.right = new Node(Integer.parseInt(currVal));
// Push it to the queue
queue.add(currNode.right);
}
i++;
}
return root;
}
public static Node inputTree(BufferedReader br) throws IOException {
return buildTree(br.readLine().trim());
}
public static void inorder(Node root) {
if (root == null) return;
inorder(root.left);
System.out.print(root.data + " ");
inorder(root.right);
}
}
class GFG {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int t;
t = Integer.parseInt(br.readLine());
while (t-- > 0) {
int n;
n = Integer.parseInt(br.readLine());
Node root = Node.inputTree(br);
Solution obj = new Solution();
int res = obj.pairsViolatingBST(n, root);
System.out.println(res);
}
}
}
// } Driver Code Ends