problem5

#What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

def leastcommonmultiple(n): #where n is a list of numbers
	k = 0
	while True:
		for x in n:
			if k


>>> top = 2432902008176640000
>>> top
2432902008176640000L
>>> list1 = range(1,21)
>>> list1
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]
>>> counter = 0
>>> answer = 0
>>> 
>>> while counter < 20:
...     for x in list1:
...             if top/x != 0:
...                     counter = 0
...                     answer = 0
...             else if top/x == 0:
  File "<stdin>", line 6
    else if top/x == 0:
          ^
SyntaxError: invalid syntax
>>> while counter < 20:
...     for x in list1:
...             if top % x != 0:
...                     counter = 0
...                     answer = 0
...             else:
...                     counter += 1
...                     answer = x
... 

yeah that was a bad approach
a REALLY FRIGGIN SLOW approach

hm so...  maybe start from teh bottom 

def productoflist(list1):
	product = 1
	for x in list1:
		product *= x
	return product



def leastcommonmultiple(list1):
	list1.sort()	
	p = 1
	top = productoflist(list1)
	counter = 0
	answer = 0
	while counter <= len(list1) and p < top:
		for x in list1:
			if p % x != 0:
				counter = 0
				answer = 0
			else:
				counter += 1
				answer = x
	return answer