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Let me rewrite this formula using a list of conjuncts:
x1 != x2
x1 < 1
x2 < 1
0 <= x1
0 <= x2
The first conjunct x1 != x2 can be rewritten into (x1 > x2) or (x1 < x2) so we have:
(x1 > x2) or (x1 < x2)
x1 < 1
x2 < 1
0 <= x1
0 <= x2
I'd like to show you that the found model (x1, x2) = (0.0, 0.0) is a solution to the delta-weakening of the original problem. FYI, here is the delta-weakening of the original problem where delta is 0.001.
(x1 > x2 - 0.001) or (x1 - 0.001 < x2)
x1 - 0.001 < 1
x2 - 0.001 < 1
-0.001 <= x1
-0.001 <= x2
When x1, x2 = 0.0, 0.0, we have:
(0 > 0 - 0.001) or (0 - 0.001 < 0)
-0.001 < 1
-0.001 < 1
-0.001 <= 0
-0.001 <= 0
You can check that all of these conjuncts are true. So this is a delta-sat solution.
Hello everyone,
Consider the following Code:
The result should be false, because the formula f is not satisfiable, but the result is true. If I print the result from the box, I get the following:
But this should not be an appropriate result.
Maybe the Issue #304 has something to do with the result as well.
Thank you in advance.
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