Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
2 / \ 1 3 Input: [2,1,3] Output: true
5 / \ 1 4 / \ 3 6 Input: [5,1,4,null,null,3,6] Output: false Explanation: The root node's value is 5 but its right child's value is 4.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def isValidBST(self, root: TreeNode) -> bool:
nodes = []
curr = root
prev_val = float('-inf')
while nodes or curr:
while curr:
nodes.append(curr)
curr = curr.left
curr = nodes.pop()
if prev_val >= curr.val:
return False
prev_val = curr.val
curr = curr.right
return True