Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as:
a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
Given the following tree [3,9,20,null,null,15,7]
:
3
/ \
9 20
/ \
15 7
Return true.
Given the following tree [1,2,2,3,3,null,null,4,4]
:
1
/ \
2 2
/ \
3 3
/ \
4 4
Return false.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def isBalanced(self, root: TreeNode) -> bool:
def depth(root: TreeNode) -> int:
if not root:
return 0
ldepth = depth(root.left)
rdepth = depth(root.right)
if ldepth == -1 or rdepth == -1 or abs(ldepth - rdepth) > 1:
return -1
return max(ldepth, rdepth) + 1
return depth(root) != -1