You are given an array nums
of non-negative integers. nums
is considered special if there exists a number x
such that there are exactly x
numbers in nums
that are greater than or equal to x
.
Notice that x
does not have to be an element in nums
.
Return x
if the array is special, otherwise, return -1
. It can be proven that if nums
is special, the value for x
is unique.
Input: nums = [3,5] Output: 2 Explanation: There are 2 values (3 and 5) that are greater than or equal to 2.
Input: nums = [0,0] Output: -1 Explanation: No numbers fit the criteria for x. If x = 0, there should be 0 numbers >= x, but there are 2. If x = 1, there should be 1 number >= x, but there are 0. If x = 2, there should be 2 numbers >= x, but there are 0. x cannot be greater since there are only 2 numbers in nums.
Input: nums = [0,4,3,0,4] Output: 3 Explanation: There are 3 values that are greater than or equal to 3.
Input: nums = [3,6,7,7,0] Output: -1
1 <= nums.length <= 100
0 <= nums[i] <= 1000
impl Solution {
pub fn special_array(mut nums: Vec<i32>) -> i32 {
nums.sort_unstable_by(|a, b| b.cmp(a));
for x in 1..=nums.len() {
if nums[x - 1] >= x as i32 && (x == nums.len() || nums[x] < x as i32) {
return x as i32;
}
}
-1
}
}