You are given an integer num
. You know that Danny Mittal will sneakily remap one of the 10
possible digits (0
to 9
) to another digit.
Return the difference between the maximum and minimum values Danny can make by remapping exactly one digit in num
.
Notes:
- When Danny remaps a digit
d1
to another digitd2
, Danny replaces all occurrences ofd1
in num withd2
. - Danny can remap a digit to itself, in which case
num
does not change. - Danny can remap different digits for obtaining minimum and maximum values respectively.
- The resulting number after remapping can contain leading zeroes.
- We mentioned "Danny Mittal" to congratulate him on being in the top 10 in Weekly Contest 326.
Input: num = 11891 Output: 99009 Explanation: To achieve the maximum value, Danny can remap the digit 1 to the digit 9 to yield 99899. To achieve the minimum value, Danny can remap the digit 1 to the digit 0, yielding 890. The difference between these two numbers is 99009.
Input: num = 90 Output: 99 Explanation: The maximum value that can be returned by the function is 99 (if 0 is replaced by 9) and the minimum value that can be returned by the function is 0 (if 9 is replaced by 0). Thus, we return 99.
1 <= num <= 108
class Solution:
def minMaxDifference(self, num: int) -> int:
num = str(num)
maxnum = int(num)
minnum = int(num.replace(num[0], '0'))
for i in range(len(num)):
if num[i] != '9':
maxnum = int(num.replace(num[i], '9'))
break
return maxnum - minnum