1030-4-程序2-6-do while.cpp

#include<stdio.h>
int main(){
      double sum = 0,term;
      	int i =0; 
      do{
      
              term = 1.0 / (i*2+1);
	if(i % 2==0)sum += term;
	else sum -= term;
	
	i++;
      }
      while( term > 1e-6);
      printf("%.6f\n",sum);
      return 0;
}