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_464.java
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_464.java
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package com.fishercoder.solutions;
import java.util.HashMap;
import java.util.Map;
/**
* 464. Can I Win
*
* In the "100 game," two players take turns adding, to a running total, any integer from 1..10.
* The player who first causes the running total to reach or exceed 100 wins.
* What if we change the game so that players cannot re-use integers?
* For example, two players might take turns drawing from a common pool of numbers of 1..15 without replacement until they reach a total >= 100.
* Given an integer maxChoosableInteger and another integer desiredTotal, determine if the first player to move can force a win, assuming both players play optimally.
*You can always assume that maxChoosableInteger will not be larger than 20 and desiredTotal will not be larger than 300.
Example
Input:
maxChoosableInteger = 10
desiredTotal = 11
Output:
false
Explanation:
No matter which integer the first player choose, the first player will lose.
The first player can choose an integer from 1 up to 10.
If the first player choose 1, the second player can only choose integers from 2 up to 10.
The second player will win by choosing 10 and get a total = 11, which is >= desiredTotal.
Same with other integers chosen by the first player, the second player will always win.
*/
public class _464 {
public static class Solution1 {
/**
* Credit: https://discuss.leetcode.com/topic/68896/java-solution-using-hashmap-with-detailed-explanation
*/
Map<Integer, Boolean> map;
boolean[] used;
public boolean canIWin(int maxChoosableInteger, int desiredTotal) {
int sum = (1 + maxChoosableInteger) * maxChoosableInteger / 2;
if (sum < desiredTotal) {
return false;
}
if (desiredTotal <= 0) {
return true;
}
map = new HashMap();
used = new boolean[maxChoosableInteger + 1];
return helper(desiredTotal);
}
public boolean helper(int desiredTotal) {
if (desiredTotal <= 0) {
return false;
}
int key = format(used);
if (!map.containsKey(key)) {
// try every unchosen number as next step
for (int i = 1; i < used.length; i++) {
if (!used[i]) {
used[i] = true;
// check whether this lead to a win (i.e. the other player lose)
if (!helper(desiredTotal - i)) {
map.put(key, true);
used[i] = false;
return true;
}
used[i] = false;
}
}
map.put(key, false);
}
return map.get(key);
}
// transfer boolean[] to an Integer
public int format(boolean[] used) {
int num = 0;
for (boolean b : used) {
num <<= 1;
if (b) {
num |= 1;
}
}
return num;
}
}
}