forked from fishercoder1534/Leetcode
-
Notifications
You must be signed in to change notification settings - Fork 1
/
_675.java
140 lines (131 loc) · 4.34 KB
/
_675.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
package com.fishercoder.solutions;
import java.util.LinkedList;
import java.util.List;
import java.util.PriorityQueue;
import java.util.Queue;
/**
* 675. Cut Off Trees for Golf Event
*
* You are asked to cut off trees in a forest for a golf event.
* The forest is represented as a non-negative 2D map, in this map:
* 0 represents the obstacle can't be reached.
* 1 represents the ground can be walked through.
*
* The place with number bigger than 1 represents a tree can be walked through,
* and this positive number represents the tree's height.
*
* You are asked to cut off all the trees in this forest in the order of tree's height -
* always cut off the tree with lowest height first.
* And after cutting, the original place has the tree will become a grass (value 1).
*
* You will start from the point (0, 0) and you should output the minimum steps you need to walk to cut off all the trees.
*
* If you can't cut off all the trees, output -1 in that situation.
* You are guaranteed that no two trees have the same height and there is at least one tree needs to be cut off.
*
* Example 1:
* Input:
* [
* [1,2,3],
* [0,0,4],
* [7,6,5]
* ]
* Output: 6
*
* Example 2:
* Input:
* [
* [1,2,3],
* [0,0,0],
* [7,6,5]
* ]
* Output: -1
*
* Example 3:
* Input:
* [
* [2,3,4],
* [0,0,5],
* [8,7,6]
* ]
* Output: 6
*
* Explanation: You started from the point (0,0) and you can cut off the tree in (0,0) directly without walking.
* Hint: size of the given matrix will not exceed 50x50.
*/
public class _675 {
public static class Solution1 {
public int cutOffTree(List<List<Integer>> forest) {
if (forest == null || forest.isEmpty() || forest.size() == 0 || forest.get(0).get(0) == 0) {
return -1;
}
int m = forest.size();
int n = forest.get(0).size();
/**cut trees in ascending order*/
PriorityQueue<Tree> heap = new PriorityQueue<>((a, b) -> a.height - b.height);
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (forest.get(i).get(j) > 1) {
/**This is important: we'll add trees that are only taller than 1!!!*/
heap.offer(new Tree(i, j, forest.get(i).get(j)));
}
}
}
int sum = 0;
Tree start = new Tree();
while (!heap.isEmpty()) {
Tree curr = heap.poll();
int step = bfs(forest, curr, start, m, n);
if (step == -1) {
return -1;
}
sum += step;
start = curr;
}
return sum;
}
private int bfs(List<List<Integer>> forest, Tree target, Tree start, int m, int n) {
int[] dirs = new int[]{0, 1, 0, -1, 0};
boolean[][] visited = new boolean[m][n];
Queue<Tree> queue = new LinkedList<>();
queue.offer(start);
visited[start.x][start.y] = true;
int step = 0;
while (!queue.isEmpty()) {
int size = queue.size();
for (int k = 0; k < size; k++) {
Tree tree = queue.poll();
if (tree.x == target.x && tree.y == target.y) {
return step;
}
for (int i = 0; i < 4; i++) {
int nextX = tree.x + dirs[i];
int nextY = tree.y + dirs[i + 1];
if (nextX < 0 || nextY < 0 || nextX >= m || nextY >= n || visited[nextX][nextY] || forest.get(nextX).get(nextY) == 0) {
continue;
}
queue.offer(new Tree(nextX, nextY, forest.get(nextX).get(nextY)));
visited[nextX][nextY] = true;
}
}
step++;
}
return -1;
}
class Tree {
int x;
int y;
int height;
public Tree(int x, int y, int height) {
this.x = x;
this.y = y;
this.height = height;
}
public Tree() {
this.x = 0;
this.y = 0;
this.height = 0;
}
}
}
}