Is there a way to access default ScalarRef instances?

[justinadkins]

I currently have a generic factory function for building object references but have run into some difficulty getting this to work with scalars. A simplified example of my original implementation looks like this:

export const buildRef = <OutT, ParentT>(
    Ref: ObjectRef<OutT, ParentT>,
    domainName: string
) =>
    builder
        .objectRef<
            DraftPublished<typeof Ref.$inferType>
        >(`DraftPublished${domainName}`)
        .implement({
            fields: (t) => ({
                draft: t.expose("draft", {
                    type: Ref,
                    nullable: true,
                }),
                published: t.expose("published", {
                    type: Ref,
                    nullable: true,
                }),
            }),
        });

I cannot seem to find a way to pass in the string value for a scalar (e.g. "Int") and have TS remain happy. I thought the simplest solution would then be to use a ScalarRef instance. I can't seem to find a way to access the ones that aren't custom. Does such a thing exist?

I welcome other feedback for tackling this problem.