Given a Weather
table, write a SQL query to find all dates' Id
s with higher temperature compared to its previous (yesterday's) dates.
+---------+------------+------------------+
| Id(INT) | Date(DATE) | Temperature(INT) |
+---------+------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------+------------------+
For example, return the following Ids for the above Weather
table:
+----+
| Id |
+----+
| 2 |
| 4 |
+----+
自连接查询,需要注意日期的比较,mysql中使用TO_DAYS
转化,否则是字符串比较。
select w1.Id from Weather w1, Weather w2
where TO_DAYS(w1.DATE) = TO_DAYS(w2.DATE) + 1
and w1.Temperature > w2.Temperature;