FAQ

Frequently Asked Questions

What is the deal with "lazy" vs "strict" positions?

In parsley-4.x.y and up, combinators are no longer totally lazy and adopt the idea of lazy and strict arguments. In general, all combinators have strict receivers.

• A strict argument/receiver indicates that the combinator intends for that argument to be parsed "immediately" without a possibility of consuming input before-hand
• A lazy argument/receiver indicates that the combinator acknowledges that input may be consumed by another argument (or the combinator itself) before the lazy argument will be executed.

Why is this important? Recursive parsers are implemented in Parsley with "knot-tying" using lazy val. When a parser appears recursively in its own definition, it needs to be kept lazy otherwise it will be evaluated during its own definition, leading to an infinite loop. Lazy positions in combinators indicate probably safe places for recursion to occur. On the other hand, the absence of input-consumption before a strict position probably indicates that recursion in that position will result in a left-recursive parser: the necessary condition for left-recursion is that a recursive call is made without having consumed input since the last recursive call. Technically, this is known as unguarded (by input consumption) recursion, with correct parsers making use of guarded recursion. This is not bullet-proof:

• Strict positions sometimes occur in combinators where they should be lazy but cannot be due to language limitations: choice, the zipped syntax, etc all fall victim to this.
• Lazy positions suggest the previously executed parsers could have consumed input, but it is not guaranteed that they actually do. As an example, LazyParsley.unary_~ can be used to make a parser lazy in an otherwise strict position, but doesn't itself consume input, so care must still be taken to ensure there is input consumed by previous arguments!

Note that a strict parser in a lazy position is still lazy!

For an example, lazy val q = (p <~ ':', q).zipped(f) would be problematic because the recursive call is used naked in a totally strict combinator (zipped). There are two ways to fix this problem:

1. Reshuffle the surrounding context to move it into a lazy position: lazy val q = (p, ':' ~> q).zipped(f) would be fine, since the right-hand side of ~> is a lazy position guarded by the input consumption of ':'.
2. Use LazyParsley.unary_~ to introduce laziness:

   import parsley.Parsley.LazyParsley
   lazy val q = (p <~ ':', ~q).zipped(f)

   Here, the unary_~ is used to just make q lazy: this is simply defined as unit ~> q, which places q into a unguarded lazy position, since unit does not consume input. The guardedness in this case comes from p <~ ':', which is guaranteed to consume a : on success.

Frequently Encountered Problems

My parser seems to infinite loop and doesn't run, even with the debug combinator

This sounds like you've run into the above issue with left-recursion. This means that a parser appears as the first possible route of exploration from itself:

lazy val bad = bad ~> ...
lazy val badExpr = Add.lift(badExpr, '+' ~> badExpr) <|> number
lazy val goodExpr = attempt((number <~ '+', goodExpr).zipped(Add)) <|> number

The first two parsers are both examples of left-recursive parsers, which are not allowed in Parsley. The third is caused by the above problem of a genuine recursive call in a strict position, and can be fixed with unary_~ or by rearranging the '+' parser as above:

lazy val goodExpr = attempt((number, '+' ~> goodExpr).zipped(Add)) <|> number
lazy val goodExpr = attempt((number <~ '+', ~goodExpr).zipped(Add)) <|> number

My parser seems to infinite loop and the debug combinator shows it spinning forever

As above you've probably made a left-recursive parser, but this time hidden the bad recursion inside an unguarded lazy position:

import parsley.Parsley.LazyParsley
lazy val badExpr = Add.lift(~badExpr, '+' ~> badExpr) <|> number

Perhaps you tried to fix the above bad parser using unary_~ even though its an unsafe recursive position?

My parser throws a BadLazinessException, what gives!

This error is thrown by the Parsley compiler when Scala would otherwise have thrown a NullPointerException during what's known as "let-finding". This is the very first phase of the pipeline, and, since Parsley does not use null anywhere in the front-end, its a symptom of a parser having been demanded before its actually been defined. So what does mean for you, the user?

Well, unfortunately, Scala doesn't give us any indication about which parser is at fault (and the Java 14 Helpful NPEs don't help much either). But here are the possible causes:

1. A parser references one that has been defined below it and it hasn't been marked as lazy val
2. A combinator doesn't have the right laziness characteristics (conventionally, Parsley defines all its combinators arguments using by-name parameters and lazy vals for those that appear multiple times in the body)
3. Be careful: builder combinators to abstract position tracking (as per the Parsley guide) also will require the same care as (2)

Now, the solution to (1) is simple, just either add a lazy val, or reorder the grammar clauses so that there is no forward referencing. Similarly, (2) is simple to fix by adding in the right laziness to the parameter. However, because Parsley is careful to make as much as possible lazy (be careful of parsley.implicits.zipped.{Zipped2, Zipped3}, however, neither of them are lazy!) you may find that you can define an entire parser without ever running into this problem, even if nothing is marked lazy: lucky you! My advice is to try and keep things ordered nicely, or mark everything as lazy; of course, laziness will have a slight runtime penalty, so its worth seeing how much of the laziness you can eliminate by just reordering.

You may be helped out by Scala here, either by an error about "crossed-initialisation" or a warning about "Reference to uninitialized value". If you see either of these, check the order and laziness of the parsers concerned!