// for floor divisions

[weepy]

x: a // b

to

x: Math.floor(a / b)

[jashkenas]

Shouldn't this be symmetric to your proposed exponential symbol? The nth root, or something like that?

[weepy]

Well it could be, but that would be much less useful! You can do the yth root of x, with x ** (1/y)

[jashkenas]

See ticket #79. Closing...