Leave specific require() as-is?

[thesoftwarephilosopher]

🙋 feature request

An option/flag to tell Parcel to ignore a specific require and leave it as-is instead of bundling it.

🤔 Expected Behavior

const options = {
   // ...
  ignoreModules: ['aws-sdk'],
};

Output file:

const AWS = require('aws-sdk'); // provided from deployment environment
// use AWS

😯 Current Behavior

No such option exists. All packages are bundled up. Output file:

const AWS = /* embedded AWS SDK source code */;
// use AWS

💁 Possible Solution

Add the option, so that the given packages are not bundled up.

🔦 Context

Parcel is used by AWS CDK to bundle up NodeJS modules for deployment to AWS Lambda.

However, AWS Lambda has a size limit on the uploaded bundle.

But AWS Lambda also provides the require function at runtime, as well as the aws-sdk.

So if Parcel had an option to leave require('aws-sdk') as-is, then I could upload my code to AWS Lambda.

💻 Examples

See above.

[mischnic]

As a workaround you try to "outsmart" Parcel with: 😬

let foo = "aws-sdk";
const AWS = require(foo);

Does this work for you?

ignoreModules: ['aws-sdk']

Parcel 2 has something like that already implemented:

{
	"app": "dist/index.js",
	"targets": {
		"default": {
			"includeNodeModules": { "aws-sdk": false }
		}
	},
	"engines": {
		"node": ">=10"
	}
}

[thesoftwarephilosopher]

The workaround works well enough for now, thanks :)