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_PyTime_FromDouble() fails to detect an integer overflow when converting a C double to a C int64_t #83458
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_PyTime_FromDouble() fails to detect an integer overflow when converting a C double to a C int64_t Python 3.7.5 (default, Nov 20 2019, 09:21:52)
[GCC 9.2.1 20191008] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import time
>>> time.sleep(9223372036.854777)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: sleep length must be non-negative |
It's a bug in _PyTime_FromDouble() which fails to detect the integer overflow when casting a C double to a C _PyTime_T (int64_t): bug in _Py_InIntegralTypeRange(_PyTime_t, d) where d is a C double. On my Fedora 31, double is a 64-bit IEEE 754 float, _PyTime_t is int64_t (64-bit signed integer). _PyTime_t maximum is 9223372036854775807. But casted as C double, it becomes 9223372036854775808: >>> int(float(9223372036854775807))
9223372036854775808 |
_PyTime_FromDouble() checks if!(_Py_DoubleInIntegralTypeRange(_PyTime_t, d)) with the macro: #define _Py_InIntegralTypeRange(type, v) (_Py_IntegralTypeMin(type) <= v && v <= _Py_IntegralTypeMax(type)) and _Py_IntegralTypeMax(type)=2**63-1. "v <= _Py_IntegralTypeMax(type)" compares a C double to a C int64_t: the compiler casts the C int64_t to a C double. The problem is that 2**63-1 casted to a C double rounds using ROUND_HALF_EVEN rounding mode which gives a number *greater* than 2**63-1: we get 2**63. To implement "v <= max", we have to round max towards zero (ROUND_DOWN), not round it using ROUND_HALF_EVEN. I didn't find a way to control the rounding mode of casting C int64_t to C double, but we can round it *afterwards* using nextafter(max, 0.0) (ROUND_DOWN). |
Similar issue in HHVM: |
Oh, clang on FreeBSD spotted a similar bug in float.__trunc__()! static PyObject *
float___trunc___impl(PyObject *self)
/*[clinic end generated code: output=dd3e289dd4c6b538 input=591b9ba0d650fdff]*/
{
double x = PyFloat_AsDouble(self);
double wholepart; /* integral portion of x, rounded toward 0 */
(void)modf(x, &wholepart);
/* Try to get out cheap if this fits in a Python int. The attempt
* to cast to long must be protected, as C doesn't define what
* happens if the double is too big to fit in a long. Some rare
* systems raise an exception then (RISCOS was mentioned as one,
* and someone using a non-default option on Sun also bumped into
* that). Note that checking for >= and <= LONG_{MIN,MAX} would
* still be vulnerable: if a long has more bits of precision than
* a double, casting MIN/MAX to double may yield an approximation,
* and if that's rounded up, then, e.g., wholepart=LONG_MAX+1 would
* yield true from the C expression wholepart<=LONG_MAX, despite
* that wholepart is actually greater than LONG_MAX.
*/
if (LONG_MIN < wholepart && wholepart < LONG_MAX) { /* <=== HERE */
const long aslong = (long)wholepart;
return PyLong_FromLong(aslong);
}
return PyLong_FromDouble(wholepart);
}
Objects/floatobject.c:881:45: warning: implicit conversion from 'long' to 'double' changes value from 9223372036854775807 to 9223372036854775808
[-Wimplicit-int-float-conversion]
if (LONG_MIN < wholepart && wholepart < LONG_MAX) {
~ ^~~~~~~~
/usr/include/sys/limits.h:64:18: note: expanded from macro 'LONG_MAX'
#define LONG_MAX __LONG_MAX /* max for a long */
^~~~~~~~~~
/usr/include/x86/_limits.h:64:20: note: expanded from macro '__LONG_MAX'
#define __LONG_MAX 0x7fffffffffffffff /* max for a long */
^~~~~~~~~~~~~~~~~~
1 warning generated. |
Is it a bug in float.__trunc__()? It seems to me that the detailed comment accounts for case of rounding up. That's why < is used instead of <=. |
C99, 6.3.1.4 Real floating and integer: """ exactly, the result is either the nearest higher or nearest lower representable value, chosen So int64_t => double is implementation defined, but not undefined. float___trunc___impl() looks correct to me (of course we can squash |
This was fixed for 3.10 and later in #101826 and its backports. Python 3.12.0a5+ (heads/main:8de59c1bb9, Mar 4 2023, 08:28:13) [Clang 14.0.0 (clang-1400.0.29.202)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import time
>>> time.sleep(9223372036.854777)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
OverflowError: timestamp out of range for platform time_t |
Note: these values reflect the state of the issue at the time it was migrated and might not reflect the current state.
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