-
Notifications
You must be signed in to change notification settings - Fork 3
/
0110-balanced-binary-tree.rb
53 lines (40 loc) · 1.02 KB
/
0110-balanced-binary-tree.rb
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
# frozen_string_literal: true
# 110. Balanced Binary Tree
# https://leetcode.com/problems/balanced-binary-tree/
# Easy
=begin
Given a binary tree, determine if it is height-balanced.
### Example 1:
Input: root = [3,9,20,null,null,15,7]
Output: true
### Example 2:
Input: root = [1,2,2,3,3,null,null,4,4]
Output: false
### Example 3:
Input: root = []
Output: true
### Constraints:
* The number of nodes in the tree is in the range [0, 5000].
* -104 <= Node.val <= 104
=end
# Definition for a binary tree node.
# class TreeNode
# attr_accessor :val, :left, :right
# def initialize(val = 0, left = nil, right = nil)
# @val = val
# @left = left
# @right = right
# end
# end
# @param {TreeNode} root
# @return {Boolean}
def is_balanced(root)
balanced_height(root, 0) >= 0
end
def balanced_height(root, height)
return height unless root
l = balanced_height(root.left, height + 1)
r = balanced_height(root.right, height + 1)
return -1 if l == -1 || r == -1 || (l - r).abs > 1
[l, r].max
end