We talked about strings in Chapter 4, but we’ll look at them in more depth now. New Rustaceans commonly get stuck on strings for a combination of three reasons: Rust’s propensity for exposing possible errors, strings being a more complicated data structure than many programmers give them credit for, and UTF-8. These factors combine in a way that can seem difficult when you’re coming from other programming languages.
It’s useful to discuss strings in the context of collections because strings
are implemented as a collection of bytes, plus some methods to provide useful
functionality when those bytes are interpreted as text. In this section, we’ll
talk about the operations on String
that every collection type has, such as
creating, updating, and reading. We’ll also discuss the ways in which String
is different from the other collections, namely how indexing into a String
is
complicated by the differences between how people and computers interpret
String
data.
We’ll first define what we mean by the term string. Rust has only one string
type in the core language, which is the string slice str
that is usually seen
in its borrowed form &str
. In Chapter 4, we talked about string slices,
which are references to some UTF-8 encoded string data stored elsewhere. String
literals, for example, are stored in the binary output of the program and are
therefore string slices.
The String
type, which is provided by Rust’s standard library rather than
coded into the core language, is a growable, mutable, owned, UTF-8 encoded
string type. When Rustaceans refer to “strings” in Rust, they usually mean the
String
and the string slice &str
types, not just one of those types.
Although this section is largely about String
, both types are used heavily in
Rust’s standard library, and both String
and string slices are UTF-8 encoded.
Rust’s standard library also includes a number of other string types, such as
OsString
, OsStr
, CString
, and CStr
. Library crates can provide even
more options for storing string data. See how those names all end in String
or Str
? They refer to owned and borrowed variants, just like the String
and
str
types you’ve seen previously. These string types can store text in
different encodings or be represented in memory in a different way, for
example. We won’t discuss these other string types in this chapter; see their
API documentation for more about how to use them and when each is appropriate.
Many of the same operations available with Vec<T>
are available with String
as well, starting with the new
function to create a string, shown in Listing
8-11.
let mut s = String::new();
Listing 8-11: Creating a new, empty String
This line creates a new empty string called s
, which we can then load data
into. Often, we’ll have some initial data that we want to start the string
with. For that, we use the to_string
method, which is available on any type
that implements the Display
trait, as string literals do. Listing 8-12 shows
two examples.
let data = "initial contents";
let s = data.to_string();
// the method also works on a literal directly:
let s = "initial contents".to_string();
Listing 8-12: Using the to_string
method to create a
String
from a string literal
This code creates a string containing initial contents
.
We can also use the function String::from
to create a String
from a string
literal. The code in Listing 8-13 is equivalent to the code from Listing 8-12
that uses to_string
.
let s = String::from("initial contents");
Listing 8-13: Using the String::from
function to create
a String
from a string literal
Because strings are used for so many things, we can use many different generic
APIs for strings, providing us with a lot of options. Some of them can seem
redundant, but they all have their place! In this case, String::from
and
to_string
do the same thing, so which you choose is a matter of style.
Remember that strings are UTF-8 encoded, so we can include any properly encoded data in them, as shown in Listing 8-14.
let hello = String::from("السلام عليكم");
let hello = String::from("Dobrý den");
let hello = String::from("Hello");
let hello = String::from("שָׁלוֹם");
let hello = String::from("नमस्ते");
let hello = String::from("こんにちは");
let hello = String::from("안녕하세요");
let hello = String::from("你好");
let hello = String::from("Olá");
let hello = String::from("Здравствуйте");
let hello = String::from("Hola");
Listing 8-14: Storing greetings in different languages in strings
All of these are valid String
values.
A String
can grow in size and its contents can change, just like the contents
of a Vec<T>
, if you push more data into it. In addition, you can conveniently
use the +
operator or the format!
macro to concatenate String
values.
We can grow a String
by using the push_str
method to append a string slice,
as shown in Listing 8-15.
let mut s = String::from("foo");
s.push_str("bar");
Listing 8-15: Appending a string slice to a String
using the push_str
method
After these two lines, s
will contain foobar
. The push_str
method takes a
string slice because we don’t necessarily want to take ownership of the
parameter. For example, the code in Listing 8-16 shows that it would be
unfortunate if we weren’t able to use s2
after appending its contents to s1
.
let mut s1 = String::from("foo");
let s2 = "bar";
s1.push_str(s2);
println!("s2 is {}", s2);
Listing 8-16: Using a string slice after appending its
contents to a String
If the push_str
method took ownership of s2
, we wouldn’t be able to print
its value on the last line. However, this code works as we’d expect!
The push
method takes a single character as a parameter and adds it to the
String
. Listing 8-17 shows code that adds the letter l to a String
using
the push
method.
let mut s = String::from("lo");
s.push('l');
Listing 8-17: Adding one character to a String
value
using push
As a result of this code, s
will contain lol
.
Often, you’ll want to combine two existing strings. One way is to use the +
operator, as shown in Listing 8-18.
let s1 = String::from("Hello, ");
let s2 = String::from("world!");
let s3 = s1 + &s2; // note s1 has been moved here and can no longer be used
Listing 8-18: Using the +
operator to combine two
String
values into a new String
value
The string s3
will contain Hello, world!
as a result of this code. The
reason s1
is no longer valid after the addition and the reason we used a
reference to s2
has to do with the signature of the method that gets called
when we use the +
operator. The +
operator uses the add
method, whose
signature looks something like this:
fn add(self, s: &str) -> String {
This isn’t the exact signature that’s in the standard library: in the standard
library, add
is defined using generics. Here, we’re looking at the signature
of add
with concrete types substituted for the generic ones, which is what
happens when we call this method with String
values. We’ll discuss generics
in Chapter 10. This signature gives us the clues we need to understand the
tricky bits of the +
operator.
First, s2
has an &
, meaning that we’re adding a reference of the second
string to the first string because of the s
parameter in the add
function:
we can only add a &str
to a String
; we can’t add two String
values
together. But wait—the type of &s2
is &String
, not &str
, as specified in
the second parameter to add
. So why does Listing 8-18 compile?
The reason we’re able to use &s2
in the call to add
is that the compiler
can coerce the &String
argument into a &str
. When we call the add
method, Rust uses a deref coercion, which here turns &s2
into &s2[..]
.
We’ll discuss deref coercion in more depth in Chapter 15. Because add
does
not take ownership of the s
parameter, s2
will still be a valid String
after this operation.
Second, we can see in the signature that add
takes ownership of self
,
because self
does not have an &
. This means s1
in Listing 8-18 will be
moved into the add
call and no longer be valid after that. So although let s3 = s1 + &s2;
looks like it will copy both strings and create a new one, this
statement actually takes ownership of s1
, appends a copy of the contents of
s2
, and then returns ownership of the result. In other words, it looks like
it’s making a lot of copies but isn’t; the implementation is more efficient
than copying.
If we need to concatenate multiple strings, the behavior of the +
operator
gets unwieldy:
let s1 = String::from("tic");
let s2 = String::from("tac");
let s3 = String::from("toe");
let s = s1 + "-" + &s2 + "-" + &s3;
At this point, s
will be tic-tac-toe
. With all of the +
and "
characters, it’s difficult to see what’s going on. For more complicated string
combining, we can use the format!
macro:
let s1 = String::from("tic");
let s2 = String::from("tac");
let s3 = String::from("toe");
let s = format!("{}-{}-{}", s1, s2, s3);
This code also sets s
to tic-tac-toe
. The format!
macro works in the same
way as println!
, but instead of printing the output to the screen, it returns
a String
with the contents. The version of the code using format!
is much
easier to read and doesn’t take ownership of any of its parameters.
In many other programming languages, accessing individual characters in a
string by referencing them by index is a valid and common operation. However,
if you try to access parts of a String
using indexing syntax in Rust, you’ll
get an error. Consider the invalid code in Listing 8-19.
let s1 = String::from("hello");
let h = s1[0];
Listing 8-19: Attempting to use indexing syntax with a String
This code will result in the following error:
error[E0277]: the trait bound `std::string::String: std::ops::Index<{integer}>` is not satisfied
-->
|
3 | let h = s1[0];
| ^^^^^ the type `std::string::String` cannot be indexed by `{integer}`
|
= help: the trait `std::ops::Index<{integer}>` is not implemented for `std::string::String`
The error and the note tell the story: Rust strings don’t support indexing. But why not? To answer that question, we need to discuss how Rust stores strings in memory.
A String
is a wrapper over a Vec<u8>
. Let’s look at some of our properly
encoded UTF-8 example strings from Listing 8-14. First, this one:
let len = String::from("Hola").len();
In this case, len
will be 4, which means the vector storing the string “Hola”
is 4 bytes long. Each of these letters takes 1 byte when encoded in UTF-8. But
what about the following line? (Note that this string begins with the capital
Cyrillic letter Ze, not the Arabic number 3.)
let len = String::from("Здравствуйте").len();
Asked how long the string is, you might say 12. However, Rust’s answer is 24: that’s the number of bytes it takes to encode “Здравствуйте” in UTF-8, because each Unicode scalar value in that string takes 2 bytes of storage. Therefore, an index into the string’s bytes will not always correlate to a valid Unicode scalar value. To demonstrate, consider this invalid Rust code:
let hello = "Здравствуйте";
let answer = &hello[0];
What should the value of answer
be? Should it be З
, the first letter? When
encoded in UTF-8, the first byte of З
is 208
and the second is 151
, so
answer
should in fact be 208
, but 208
is not a valid character on its
own. Returning 208
is likely not what a user would want if they asked for the
first letter of this string; however, that’s the only data that Rust has at
byte index 0. Users generally don’t want the byte value returned, even if the
string contains only Latin letters: if &"hello"[0]
were valid code that
returned the byte value, it would return 104
, not h
. To avoid returning an
unexpected value and causing bugs that might not be discovered immediately,
Rust doesn’t compile this code at all and prevents misunderstandings early in
the development process.
Another point about UTF-8 is that there are actually three relevant ways to look at strings from Rust’s perspective: as bytes, scalar values, and grapheme clusters (the closest thing to what we would call letters).
If we look at the Hindi word “नमस्ते” written in the Devanagari script, it is
stored as a vector of u8
values that looks like this:
[224, 164, 168, 224, 164, 174, 224, 164, 184, 224, 165, 141, 224, 164, 164,
224, 165, 135]
That’s 18 bytes and is how computers ultimately store this data. If we look at
them as Unicode scalar values, which are what Rust’s char
type is, those
bytes look like this:
['न', 'म', 'स', '्', 'त', 'े']
There are six char
values here, but the fourth and sixth are not letters:
they’re diacritics that don’t make sense on their own. Finally, if we look at
them as grapheme clusters, we’d get what a person would call the four letters
that make up the Hindi word:
["न", "म", "स्", "ते"]
Rust provides different ways of interpreting the raw string data that computers store so that each program can choose the interpretation it needs, no matter what human language the data is in.
A final reason Rust doesn’t allow us to index into a String
to get a
character is that indexing operations are expected to always take constant time
(O(1)). But it isn’t possible to guarantee that performance with a String
,
because Rust would have to walk through the contents from the beginning to the
index to determine how many valid characters there were.
Indexing into a string is often a bad idea because it’s not clear what the
return type of the string-indexing operation should be: a byte value, a
character, a grapheme cluster, or a string slice. Therefore, Rust asks you to
be more specific if you really need to use indices to create string slices. To
be more specific in your indexing and indicate that you want a string slice,
rather than indexing using []
with a single number, you can use []
with a
range to create a string slice containing particular bytes:
let hello = "Здравствуйте";
let s = &hello[0..4];
Here, s
will be a &str
that contains the first 4 bytes of the string.
Earlier, we mentioned that each of these characters was 2 bytes, which means
s
will be Зд
.
What would happen if we used &hello[0..1]
? The answer: Rust would panic at
runtime in the same way as if an invalid index were accessed in a vector:
thread 'main' panicked at 'byte index 1 is not a char boundary; it is inside 'З' (bytes 0..2) of `Здравствуйте`', src/libcore/str/mod.rs:2188:4
You should use ranges to create string slices with caution, because doing so can crash your program.
Fortunately, you can access elements in a string in other ways.
If you need to perform operations on individual Unicode scalar values, the best
way to do so is to use the chars
method. Calling chars
on “नमस्ते” separates
out and returns six values of type char
, and you can iterate over the result
to access each element:
for c in "नमस्ते".chars() {
println!("{}", c);
}
This code will print the following:
न
म
स
्
त
े
The bytes
method returns each raw byte, which might be appropriate for your
domain:
for b in "नमस्ते".bytes() {
println!("{}", b);
}
This code will print the 18 bytes that make up this String
:
224
164
// --snip--
165
135
But be sure to remember that valid Unicode scalar values may be made up of more than 1 byte.
Getting grapheme clusters from strings is complex, so this functionality is not provided by the standard library. Crates are available on crates.io if this is the functionality you need.
To summarize, strings are complicated. Different programming languages make
different choices about how to present this complexity to the programmer. Rust
has chosen to make the correct handling of String
data the default behavior
for all Rust programs, which means programmers have to put more thought into
handling UTF-8 data upfront. This trade-off exposes more of the complexity of
strings than is apparent in other programming languages, but it prevents you
from having to handle errors involving non-ASCII characters later in your
development life cycle.
Let’s switch to something a bit less complex: hash maps!