declare plugin for gulp 3
First, install gulp-declare
as a development dependency:
npm install --save-dev gulp-declare
Then, add it to your gulpfile.js
:
var declare = require('gulp-declare');
var concat = require('gulp-concat');
gulp.task('models', function() {
// Define each model as a property of a namespace according to its filename
gulp.src(['client/models/*.js'])
.pipe(declare({
namespace: 'MyApp.models',
noRedeclare: true // Avoid duplicate declarations
}))
.pipe(concat('models.js')) // Combine into a single file
.pipe(gulp.dest('build/js/'));
});
Type: String
Default: "this"
The namespace in which the file contents will be assigned. Use dot notation (e.g. MyApp.templates
) for nested namespaces.
For example, if the namespace is MyApp.templates
and a file is named App.Header.js
, the following declaration will be added:
this["MyApp"] = this["MyApp"] || {};
this["MyApp"]["templates"] = this["MyApp"]["templates"] || {};
this["MyApp"]["templates"]["App"] = this["MyApp"]["templates"]["App"] || {};
this["MyApp"]["templates"]["App"]["Header"] = /* File contents from App.Header.js */;
If the default value of "this"
is provided, namespace declaration will be determined soley by the filename and output of options.processName
. That is, a file names MyApp.templates.App.Header.js
will result in the same declaration as above.
Type: Function
Default: Strip file extension
This option accepts a function which takes one argument (the path to the file) and returns a string which will be used as the key for object. By default, the filename minus the extension is used.
This function should return a namespace path in dot notation, such as Prop.sub.item
, which is then combined with options.namespace
. See options.namespace
above for an example.
See declare.processNameByPath
to generate namespace paths based on directory structure.
Type: String
Default: \n
The separator to use between declarations.
Type: Boolean
Default: false
If true
, parts of the namespace that were declared as a result of previous files in the stream will not be redeclared. For instance, if the stream contains the following files:
- Main.Content.js
- Main.Header.js
- Main.Footer.js
And if declare
is invoked with { namespace: 'MyApp', noRedeclare: true }
, the contents of the streamed files will look like this:
Main.Content.js
this["MyApp"] = this["MyApp"] || {};
this["MyApp"]["Main"] = this["MyApp"]["Main"] || {};
this["MyApp"]["Main"]["Content"] = /* File contents from Main.Content.js */;
Main.Header.js
this["MyApp"]["Main"]["Header"] = /* File contents from Main.Header.js */;
Main.Footer.js
this["MyApp"]["Main"]["Footer"] = /* File contents from Main.Footer.js */;
This option makes the most sense when you're concatenating files later and want to minimize duplicate declarations. Regardless of this option, gulp-declare
will never clobber existing namespaces or their properties.
Type: String
Default: this
The root object to declare the namespace within. Defaults to this
(which is equal to window
in the browser).
This option is prepended to the assignment statement, so special characters or operators such as -
should be avoided as they will result in an invalid left-hand assignment error.
When using Node or Browserify, you can specify root: 'module.exports'
with no namespace if you would like to assign as properties of an exported module:
gulp.src(['models/*.js'])
.pipe(declare({
root: 'module.exports', // Declare as properties of module.exports
noRedeclare: true // Avoid duplicate declarations
})
.pipe(concat('models.js'))
.pipe(gulp.dest('build/js/'));
Which results in the following templates.js
:
module.exports["App"] = module.exports["App"] || {};
module.exports["App"]["Main"] = /* File contents from App.Main.js */;
module.exports["App"]["Header"] = /* File contents from App.Header.js */;
module.exports["App"]["Footer"] = /* File contents from App.Footer.js */;
Pass this method as options.processName
so the path within the namespace matches the path in the filesystem combined with dot notation from the filename:
The separatorFormat
is optional that it changes the dot notation in other notation type.
gulp.src(['templates/**/*.html'])
.pipe(domly()) // Compile HTML to document fragment builder functions
.pipe(declare({
namespace: 'NS', // Use NS as the base namespace
noRedeclare: true, // Avoid duplicate declarations
processName: declare.processNameByPath // Include the path as part of the sub-namespace
})
.pipe(concat('models.js'))
.pipe(gulp.dest('build/js/'));
The above configuration will result in the following mapping:
File path | Namespace path |
---|---|
templates/App.hbs | NS.templates.App |
templates/App/header.hbs | NS.templates.App.header |
templates/App/content.initial.hbs | NS.templates.App.content.initial |
templates/Other.item.hbs | NS.templates.Other.item |
Note: In the above example, NS.templates.App.header
is a function that is stored as a property of the NS.templates.App
function. As everything in JavaScript is an object, even functions, this is perfectly valid and works in all environments. If this hurts your brain, store templates/App.hbs
as templates/App/main.hbs
and access it as NS.templates.App.main
.
If you want to remove or change part of the path, you can define your own options.processName
and use declare.processNameByPath()
within it. The following example results in the same namespace paths as above with a different directory structure:
gulp.src(['client/templates/**/*.html'])
.pipe(domly()) // Compile HTML to document fragment builder functions
.pipe(declare({
namespace: 'NS.templates', // Declare within NS.templates
noRedeclare: true, // Avoid duplicate declarations
processName: function(filePath) {
// Drop the client/templates/ folder from the namespace path
return declare.processNameByPath(filePath.replace('client/templates/', ''));
}
})
.pipe(concat('templates.js'))
.pipe(gulp.dest('build/js/'));