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Lift restrictions for matching of binaries and maps
There has always been an implementation limitation for matching of binaries (for technical reasons). For example: foo(Bin) -> <<A:8>> = <<X:4,Y:4>> = Bin, {A,X,Y}. This would fail to compile with the following message: t.erl:5:5: binary patterns cannot be matched in parallel using '=' % 5| <<A:8>> = <<X:4,Y:4>> = Bin, % | ^ This commit lifts this restriction, making the example legal. A restriction for map matching is also lifted, but before we can describe that, we'll need a digression to talk about the `=` operator. The `=` operator can be used for two similar but slightly differently purposes. When used in a pattern, for example in a function head, both the left-hand and right-hand side operands must be patterns: Pattern1 = Pattern2 For example: bar(#{a := A} = #{b := B}) -> {A, B}. The following example will not compile because the right-hand side is not a pattern but an expression: wrong(#{a := A} = #{b => B}) -> {A, B}. t.erl:4:23: illegal pattern % 4| wrong(#{a := A} = #{b => B}) -> {A, B}. % | ^ Used in this context, the `=` operator does not imply that the two patterns are matched in any particular order. Attempting to use a variable matched out on the left-hand side on the right-hand side, or vice versa, will fail: also_wrong1(#{B := A} = #{b := B}) -> {A,B}. also_wrong2(#{a := A} = #{A := B}) -> {A,B}. t.erl:6:15: variable 'B' is unbound % 6| also_wrong1(#{B := A} = #{b := B}) -> {A,B}. % | ^ t.erl:7:27: variable 'A' is unbound % 7| also_wrong2(#{a := A} = #{A := B}) -> {A,B}. % | ^ The other way to use `=` is in a function body. Used in this way, the right-hand side must be an expression: Pattern = Expression For example: foobar(Value) -> #{a := A} = #{a => Value}, A. Used in this context, the right-hand side of `=` must **not** be a pattern: illegal_foobar(Value) -> #{a := A} = #{a := Value}, A. t.erl:18:21: only association operators '=>' are allowed in map construction % 18| #{a := A} = #{a := Value}, % | ^ When used in a body context, the value of the `=` operator is the value of its right-hand side operand. When multiple `=` operators are combined, they are evaluted from right to left. That means that any number of patterns can be matched at once: Pattern1 = Pattern2 = ... = PatternN = Expr Given that there is a well-defined evaluation order, one would except that the following example would be legal: baz(M) -> #{K := V} = #{k := K} = M, V. It is not. In Erlang/OTP 25 or earlier, the compilation fails with the following message: t.erl:28:7: variable 'K' is unbound % 28| #{K := V} = #{k := K} = M, % | ^ That restriction is now lifted, making the example legal. Closes erlang#6348
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