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4 changes: 2 additions & 2 deletions exercises/practice/affine-cipher/.docs/instructions.md
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Expand Up @@ -18,10 +18,10 @@ E(x) = (ai + b) mod m

Where:

- `i` is the letter's index from `0` to the length of the alphabet - 1
- `i` is the letter's index from `0` to the length of the alphabet - 1.
- `m` is the length of the alphabet.
For the Roman alphabet `m` is `26`.
- `a` and `b` are integers which make the encryption key
- `a` and `b` are integers which make up the encryption key.

Values `a` and `m` must be _coprime_ (or, _relatively prime_) for automatic decryption to succeed, i.e., they have number `1` as their only common factor (more information can be found in the [Wikipedia article about coprime integers][coprime-integers]).
In case `a` is not coprime to `m`, your program should indicate that this is an error.
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2 changes: 1 addition & 1 deletion exercises/practice/bank-account/.docs/instructions.md
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Expand Up @@ -3,7 +3,7 @@
Your task is to implement bank accounts supporting opening/closing, withdrawals, and deposits of money.

As bank accounts can be accessed in many different ways (internet, mobile phones, automatic charges), your bank software must allow accounts to be safely accessed from multiple threads/processes (terminology depends on your programming language) in parallel.
For example, there may be many deposits and withdrawals occurring in parallel; you need to ensure there is no [race conditions][wikipedia] between when you read the account balance and set the new balance.
For example, there may be many deposits and withdrawals occurring in parallel; you need to ensure there are no [race conditions][wikipedia] between when you read the account balance and set the new balance.

It should be possible to close an account; operations against a closed account must fail.

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2 changes: 1 addition & 1 deletion exercises/practice/go-counting/.docs/instructions.md
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Expand Up @@ -25,7 +25,7 @@ Empty spaces represent empty intersections.

To be more precise an empty intersection is part of a player's territory if all of its neighbors are either stones of that player or empty intersections that are part of that player's territory.

For more information see [wikipedia][go-wikipedia] or [Sensei's Library][go-sensei].
For more information see [Wikipedia][go-wikipedia] or [Sensei's Library][go-sensei].

[go-wikipedia]: https://en.wikipedia.org/wiki/Go_%28game%29
[go-sensei]: https://senseis.xmp.net/
28 changes: 25 additions & 3 deletions exercises/practice/killer-sudoku-helper/.docs/instructions.md
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Expand Up @@ -20,7 +20,17 @@ In a 3-digit cage with a sum of 7, there is only one valid combination: 124.
- 1 + 2 + 4 = 7
- Any other combination that adds up to 7, e.g. 232, would violate the rule of not repeating digits within a cage.

![Sudoku grid, with three killer cages that are marked as grouped together. The first killer cage is in the 3×3 box in the top left corner of the grid. The middle column of that box forms the cage, with the followings cells from top to bottom: first cell contains a 1 and a pencil mark of 7, indicating a cage sum of 7, second cell contains a 2, third cell contains a 5. The numbers are highlighted in red to indicate a mistake. The second killer cage is in the central 3×3 box of the grid. The middle column of that box forms the cage, with the followings cells from top to bottom: first cell contains a 1 and a pencil mark of 7, indicating a cage sum of 7, second cell contains a 2, third cell contains a 4. None of the numbers in this cage are highlighted and therefore don't contain any mistakes. The third killer cage follows the outside corner of the central 3×3 box of the grid. It is made up of the following three cells: the top left cell of the cage contains a 2, highlighted in red, and a cage sum of 7. The top right cell of the cage contains a 3. The bottom right cell of the cage contains a 2, highlighted in red. All other cells are empty.][one-solution-img]
![Sudoku grid, with three killer cages that are marked as grouped together.
The first killer cage is in the 3×3 box in the top left corner of the grid.
The middle column of that box forms the cage, with the followings cells from top to bottom: first cell contains a 1 and a pencil mark of 7, indicating a cage sum of 7, second cell contains a 2, third cell contains a 5.
The numbers are highlighted in red to indicate a mistake.
The second killer cage is in the central 3×3 box of the grid.
The middle column of that box forms the cage, with the followings cells from top to bottom: first cell contains a 1 and a pencil mark of 7, indicating a cage sum of 7, second cell contains a 2, third cell contains a 4.
None of the numbers in this cage are highlighted and therefore don't contain any mistakes.
The third killer cage follows the outside corner of the central 3×3 box of the grid.
It is made up of the following three cells: the top left cell of the cage contains a 2, highlighted in red, and a cage sum of 7.
The top right cell of the cage contains a 3.
The bottom right cell of the cage contains a 2, highlighted in red. All other cells are empty.][one-solution-img]

## Example 2: Cage with several combinations

Expand All @@ -31,7 +41,13 @@ In a 2-digit cage with a sum 10, there are 4 possible combinations:
- 37
- 46

![Sudoku grid, all squares empty except for the middle column, column 5, which has 8 rows filled. Each continguous two rows form a killer cage and are marked as grouped together. From top to bottom: first group is a cell with value 1 and a pencil mark indicating a cage sum of 10, cell with value 9. Second group is a cell with value 2 and a pencil mark of 10, cell with value 8. Third group is a cell with value 3 and a pencil mark of 10, cell with value 7. Fourth group is a cell with value 4 and a pencil mark of 10, cell with value 6. The last cell in the column is empty.][four-solutions-img]
![Sudoku grid, all squares empty except for the middle column, column 5, which has 8 rows filled.
Each continguous two rows form a killer cage and are marked as grouped together.
From top to bottom: first group is a cell with value 1 and a pencil mark indicating a cage sum of 10, cell with value 9.
Second group is a cell with value 2 and a pencil mark of 10, cell with value 8.
Third group is a cell with value 3 and a pencil mark of 10, cell with value 7.
Fourth group is a cell with value 4 and a pencil mark of 10, cell with value 6.
The last cell in the column is empty.][four-solutions-img]

## Example 3: Cage with several combinations that is restricted

Expand All @@ -42,7 +58,13 @@ In a 2-digit cage with a sum 10, where the column already contains a 1 and a 4,

19 and 46 are not possible due to the 1 and 4 in the column according to standard Sudoku rules.

![Sudoku grid, all squares empty except for the middle column, column 5, which has 8 rows filled. The first row contains a 4, the second is empty, and the third contains a 1. The 1 is highlighted in red to indicate a mistake. The last 6 rows in the column form killer cages of two cells each. From top to bottom: first group is a cell with value 2 and a pencil mark indicating a cage sum of 10, cell with value 8. Second group is a cell with value 3 and a pencil mark of 10, cell with value 7. Third group is a cell with value 1, highlighted in red, and a pencil mark of 10, cell with value 9.][not-possible-img]
![Sudoku grid, all squares empty except for the middle column, column 5, which has 8 rows filled.
The first row contains a 4, the second is empty, and the third contains a 1.
The 1 is highlighted in red to indicate a mistake.
The last 6 rows in the column form killer cages of two cells each.
From top to bottom: first group is a cell with value 2 and a pencil mark indicating a cage sum of 10, cell with value 8.
Second group is a cell with value 3 and a pencil mark of 10, cell with value 7.
Third group is a cell with value 1, highlighted in red, and a pencil mark of 10, cell with value 9.][not-possible-img]

## Trying it yourself

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3 changes: 2 additions & 1 deletion exercises/practice/luhn/.docs/instructions.md
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Expand Up @@ -22,7 +22,8 @@ The first step of the Luhn algorithm is to double every second digit, starting f
We will be doubling

```text
4_3_ 3_9_ 0_4_ 6_6_
4539 3195 0343 6467
↑ ↑ ↑ ↑ ↑ ↑ ↑ ↑ (double these)
```

If doubling the number results in a number greater than 9 then subtract 9 from the product.
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3 changes: 2 additions & 1 deletion exercises/practice/matching-brackets/.docs/instructions.md
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# Instructions

Given a string containing brackets `[]`, braces `{}`, parentheses `()`, or any combination thereof, verify that any and all pairs are matched and nested correctly.
The string may also contain other characters, which for the purposes of this exercise should be ignored.
Any other characters should be ignored.
For example, `"{what is (42)}?"` is balanced and `"[text}"` is not.
8 changes: 8 additions & 0 deletions exercises/practice/matching-brackets/.docs/introduction.md
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# Introduction

You're given the opportunity to write software for the Bracketeer™, an ancient but powerful mainframe.
The software that runs on it is written in a proprietary language.
Much of its syntax is familiar, but you notice _lots_ of brackets, braces and parentheses.
Despite the Bracketeer™ being powerful, it lacks flexibility.
If the source code has any unbalanced brackets, braces or parentheses, the Bracketeer™ crashes and must be rebooted.
To avoid such a scenario, you start writing code that can verify that brackets, braces, and parentheses are balanced before attempting to run it on the Bracketeer™.
27 changes: 24 additions & 3 deletions exercises/practice/pascals-triangle/.docs/instructions.md
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# Instructions

Compute Pascal's triangle up to a given number of rows.
Your task is to output the first N rows of Pascal's triangle.

In Pascal's Triangle each number is computed by adding the numbers to the right and left of the current position in the previous row.
[Pascal's triangle][wikipedia] is a triangular array of positive integers.

In Pascal's triangle, the number of values in a row is equal to its row number (which starts at one).
Therefore, the first row has one value, the second row has two values, and so on.

The first (topmost) row has a single value: `1`.
Subsequent rows' values are computed by adding the numbers directly to the right and left of the current position in the previous row.

If the previous row does _not_ have a value to the left or right of the current position (which only happens for the leftmost and rightmost positions), treat that position's value as zero (effectively "ignoring" it in the summation).

## Example

Let's look at the first 5 rows of Pascal's Triangle:

```text
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
# ... etc
```

The topmost row has one value, which is `1`.

The leftmost and rightmost values have only one preceding position to consider, which is the position to its right respectively to its left.
With the topmost value being `1`, it follows from this that all the leftmost and rightmost values are also `1`.

The other values all have two positions to consider.
For example, the fifth row's (`1 4 6 4 1`) middle value is `6`, as the values to its left and right in the preceding row are `3` and `3`:

[wikipedia]: https://en.wikipedia.org/wiki/Pascal%27s_triangle
22 changes: 22 additions & 0 deletions exercises/practice/pascals-triangle/.docs/introduction.md
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# Introduction

With the weather being great, you're not looking forward to spending an hour in a classroom.
Annoyed, you enter the class room, where you notice a strangely satisfying triangle shape on the blackboard.
Whilst waiting for your math teacher to arrive, you can't help but notice some patterns in the triangle: the outer values are all ones, each subsequent row has one more value than its previous row and the triangle is symmetrical.
Weird!

Not long after you sit down, your teacher enters the room and explains that this triangle is the famous [Pascal's triangle][wikipedia].

Over the next hour, your teacher reveals some amazing things hidden in this triangle:

- It can be used to compute how many ways you can pick K elements from N values.
- It contains the Fibonacci sequence.
- If you color odd and even numbers differently, you get a beautiful pattern called the [Sierpiński triangle][wikipedia-sierpinski-triangle].

The teacher implores you and your classmates to lookup other uses, and assures you that there are lots more!
At that moment, the school bell rings.
You realize that for the past hour, you were completely absorbed in learning about Pascal's triangle.
You quickly grab your laptop from your bag and go outside, ready to enjoy both the sunshine _and_ the wonders of Pascal's triangle.

[wikipedia]: https://en.wikipedia.org/wiki/Pascal%27s_triangle
[wikipedia-sierpinski-triangle]: https://en.wikipedia.org/wiki/Sierpi%C5%84ski_triangle
2 changes: 1 addition & 1 deletion exercises/practice/poker/.docs/instructions.md
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Expand Up @@ -2,6 +2,6 @@

Pick the best hand(s) from a list of poker hands.

See [wikipedia][poker-hands] for an overview of poker hands.
See [Wikipedia][poker-hands] for an overview of poker hands.

[poker-hands]: https://en.wikipedia.org/wiki/List_of_poker_hands
31 changes: 17 additions & 14 deletions exercises/practice/space-age/.docs/instructions.md
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# Instructions

Given an age in seconds, calculate how old someone would be on:
Given an age in seconds, calculate how old someone would be on a planet in our Solar System.

- Mercury: orbital period 0.2408467 Earth years
- Venus: orbital period 0.61519726 Earth years
- Earth: orbital period 1.0 Earth years, 365.25 Earth days, or 31557600 seconds
- Mars: orbital period 1.8808158 Earth years
- Jupiter: orbital period 11.862615 Earth years
- Saturn: orbital period 29.447498 Earth years
- Uranus: orbital period 84.016846 Earth years
- Neptune: orbital period 164.79132 Earth years
One Earth year equals 365.25 Earth days, or 31,557,600 seconds.
If you were told someone was 1,000,000,000 seconds old, their age would be 31.69 Earth-years.

So if you were told someone were 1,000,000,000 seconds old, you should
be able to say that they're 31.69 Earth-years old.
For the other planets, you have to account for their orbital period in Earth Years:

If you're wondering why Pluto didn't make the cut, go watch [this YouTube video][pluto-video].
| Planet | Orbital period in Earth Years |
| ------- | ----------------------------- |
| Mercury | 0.2408467 |
| Venus | 0.61519726 |
| Earth | 1.0 |
| Mars | 1.8808158 |
| Jupiter | 11.862615 |
| Saturn | 29.447498 |
| Uranus | 84.016846 |
| Neptune | 164.79132 |

Note: The actual length of one complete orbit of the Earth around the sun is closer to 365.256 days (1 sidereal year).
~~~~exercism/note
The actual length of one complete orbit of the Earth around the sun is closer to 365.256 days (1 sidereal year).
The Gregorian calendar has, on average, 365.2425 days.
While not entirely accurate, 365.25 is the value used in this exercise.
See [Year on Wikipedia][year] for more ways to measure a year.
[pluto-video]: https://www.youtube.com/watch?v=Z_2gbGXzFbs
[year]: https://en.wikipedia.org/wiki/Year#Summary
~~~~
20 changes: 20 additions & 0 deletions exercises/practice/space-age/.docs/introduction.md
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# Introduction

The year is 2525 and you've just embarked on a journey to visit all planets in the Solar System (Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus and Neptune).
The first stop is Mercury, where customs require you to fill out a form (bureaucracy is apparently _not_ Earth-specific).
As you hand over the form to the customs officer, they scrutinize it and frown.
"Do you _really_ expect me to believe you're just 50 years old?
You must be closer to 200 years old!"

Amused, you wait for the customs officer to start laughing, but they appear to be dead serious.
You realize that you've entered your age in _Earth years_, but the officer expected it in _Mercury years_!
As Mercury's orbital period around the sun is significantly shorter than Earth, you're actually a lot older in Mercury years.
After some quick calculations, you're able to provide your age in Mercury Years.
The customs officer smiles, satisfied, and waves you through.
You make a mental note to pre-calculate your planet-specific age _before_ future customs checks, to avoid such mix-ups.

~~~~exercism/note
If you're wondering why Pluto didn't make the cut, go watch [this YouTube video][pluto-video].
[pluto-video]: https://www.youtube.com/watch?v=Z_2gbGXzFbs
~~~~
2 changes: 1 addition & 1 deletion exercises/practice/yacht/.meta/config.json
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Expand Up @@ -17,6 +17,6 @@
]
},
"blurb": "Score a single throw of dice in the game Yacht.",
"source": "James Kilfiger, using wikipedia",
"source": "James Kilfiger, using Wikipedia",
"source_url": "https://en.wikipedia.org/wiki/Yacht_(dice_game)"
}
18 changes: 9 additions & 9 deletions exercises/practice/zebra-puzzle/.docs/instructions.md
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Expand Up @@ -12,20 +12,20 @@ The following 15 statements are all known to be true:
1. There are five houses.
2. The Englishman lives in the red house.
3. The Spaniard owns the dog.
4. Coffee is drunk in the green house.
4. The person in the green house drinks coffee.
5. The Ukrainian drinks tea.
6. The green house is immediately to the right of the ivory house.
7. The Old Gold smoker owns snails.
8. Kools are smoked in the yellow house.
9. Milk is drunk in the middle house.
7. The snail owner likes to go dancing.
8. The person in the yellow house is a painter.
9. The person in the middle house drinks milk.
10. The Norwegian lives in the first house.
11. The man who smokes Chesterfields lives in the house next to the man with the fox.
12. Kools are smoked in the house next to the house where the horse is kept.
13. The Lucky Strike smoker drinks orange juice.
14. The Japanese smokes Parliaments.
11. The person who enjoys reading lives in the house next to the person with the fox.
12. The painter's house is next to the house with the horse.
13. The person who plays football drinks orange juice.
14. The Japanese person plays chess.
15. The Norwegian lives next to the blue house.

Additionally, each of the five houses is painted a different color, and their inhabitants are of different national extractions, own different pets, drink different beverages and smoke different brands of cigarettes.
Additionally, each of the five houses is painted a different color, and their inhabitants are of different national extractions, own different pets, drink different beverages and engage in different hobbies.

~~~~exercism/note
There are 24 billion (5!⁵ = 24,883,200,000) possible solutions, so try ruling out as many solutions as possible.
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2 changes: 1 addition & 1 deletion exercises/practice/zebra-puzzle/.docs/introduction.md
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# Introduction

The Zebra Puzzle is a famous logic puzzle in which there are five houses, each painted a different color.
The houses have different inhabitants, who have different nationalities, own different pets, drink different beverages and smoke different brands of cigarettes.
The houses have different inhabitants, who have different nationalities, own different pets, drink different beverages and enjoy different hobbies.

To help you solve the puzzle, you're given 15 statements describing the solution.
However, only by combining the information in _all_ statements will you be able to find the solution to the puzzle.
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