解決：SQL审核->SQL分析页面，当SQL中包含 != 的时候，会导致查看按钮显示异常，无法展示相应的SQL建议的问题

hhyo · Oct 25, 2020 · 1c427f9 · 1c427f9
1 parent bf21f79
commit 1c427f9
Showing 1 changed file with 1 addition and 1 deletion.
diff --git a/sql/templates/sqlanalyze.html b/sql/templates/sqlanalyze.html
@@ -338,7 +338,7 @@ <h4 class="modal-title text-danger">分析报告</h4>
                         title: '分析报告',
                         field: 'operation',
                         formatter: function (value, row, index) {
-                            return "<button class=\"btn btn-info btn-xs\" report=\"" + row.report + "\"\n" + "onclick=\"getReport(this)\" >查看\n" + "</button>"
+                            return "<button class=\"btn btn-info btn-xs\" report=\"" + row.report.replace(/"<>\.*/gm,'<\>才是标准SQL中的不等于运算符') + "\"\n" + "onclick=\"getReport(this)\" >查看\n" + "</button>"
                         }
                     }],
                     onLoadSuccess: function () {