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analyze: move
Option<&mut T>
on last use instead of reborrowing (#1179
) Currently, we reborrow `Option<&mut T>` at most use sites by calling `p.as_deref_mut()`. This creates a new reference that's tied to the lifetime of the `Option`, rather than the lifetime of the original reference. This is fine for temporaries and local variables, but creates a problem when returning the result from the current function: ```Rust fn f(x: Option<&mut Foo>) -> Option<&mut i32> { x.as_deref_mut().map(|x| &mut x.field) } ``` This produces a borrowck error because `as_deref_mut` has the signature `(&'b mut Option<&'a mut T>) -> Option<&'b mut T>`, meaning the result must not outlive `x`. The fix here is to consume `x`: ```Rust fn f(x: Option<&mut Foo>) -> Option<&mut i32> { // No `.as_deref_mut()` - `x` is moved into `map()` x.map(|x| &mut x.field) } ``` In this case, `map` has the signature `(Option<&'a mut T>, [closure]) -> Option<&'a mut i32>`, preserving the lifetime of the input reference. This branch adds an analysis to identify the "last use" of each local variable and modifies the rewriting rules around `Option<T>` to omit `.as_deref_mut()` at the last use.
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