HttpURI toURI passes all info #11468
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cowwoc
reviewed
Feb 29, 2024
| @@ -265,8 +264,7 @@ default URI toURI() | |||
| { | |||
| try | |||
| { | |||
| String query = getQuery(); | |||
| return new URI(getScheme(), null, getHost(), getPort(), getPath(), query == null ? null : UrlEncoded.decodeString(query), null); | |||
| return new URI(toString()); | |||
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Consider using URI.create(String) instead if you're okay with throwing IllegalArgumentException instead of RuntimeException.
sbordet
approved these changes
Feb 29, 2024
|
EEEK! This was bad! |
|
The multi-parameter |
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Fix #11465 and #7750
HttpURI.toURI user and fragment are retained.
Use to URI(String) constructor, as all URI constructors will parse the URI anyway.