The on function #3104
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by
markostanimirovic
lukhomdingi
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Hello, Could you provide a proper way of using the on function with the following syntax:
|
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Answered by
markostanimirovic
Aug 2, 2021
Replies: 1 comment
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However, if you want to use export const onLoginSuccess = on<fromAuth.State, [typeof AuthApiActions.loginSuccess]>(
AuthApiActions.loginSuccess,
(state, { user }) => ({ ...state, user })
); |
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markostanimirovic
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@lukhomdingi
on
function is intended for use within thecreateReducer
function. Then the type of action creators will be automatically inferred.However, if you want to use
on
function separately, you can manually declare the type of action creator array: