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tests/ui/raw-ref-op/amp-raw-without-mut-const-is-a-normal-borrow.rs
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//! The token sequence `&raw` *only* starts a raw borrow expr if it's immediately | ||
//! followed by either `const` or `mut`. If that's not the case, the `&` denotes | ||
//! the start of a normal borrow expr where `raw` is interpreted as a regular | ||
//! identifier and thus denotes the start of a path expr. | ||
//! | ||
//! This test ensures that we never commit too early/overzealously in the parser | ||
//! when encountering the sequence `&raw` (even during parse error recovery) so | ||
//! as not to regress preexisting code. | ||
//@ check-pass | ||
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fn main() { // the odd formatting in here is intentional | ||
let raw = 0; | ||
let _ = &raw; | ||
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let raw = 0; | ||
let local = 1; | ||
let _ = &raw *local; | ||
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let raw = |_| (); | ||
let local = [0]; | ||
let _ = &raw (local[0]); | ||
} | ||
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macro_rules! check { | ||
($e:expr) => { compile_error!("expr"); }; | ||
(&raw $e:expr) => {}; | ||
} | ||
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check!(&raw local); |