Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

E0716: clarify that equivalent code example is erroneous #86477

Merged
merged 1 commit into from
Jul 5, 2021
Merged
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
6 changes: 4 additions & 2 deletions compiler/rustc_error_codes/src/error_codes/E0716.md
Original file line number Diff line number Diff line change
Expand Up @@ -14,14 +14,16 @@ Here, the expression `&foo()` is borrowing the expression `foo()`. As `foo()` is
a call to a function, and not the name of a variable, this creates a
**temporary** -- that temporary stores the return value from `foo()` so that it
can be borrowed. You could imagine that `let p = bar(&foo());` is equivalent to
this:
the following, which uses an explicit temporary variable.

Erroneous code example:

```compile_fail,E0597
# fn foo() -> i32 { 22 }
# fn bar(x: &i32) -> &i32 { x }
let p = {
let tmp = foo(); // the temporary
bar(&tmp)
bar(&tmp) // error: `tmp` does not live long enough
}; // <-- tmp is freed as we exit this block
let q = p;
```
Expand Down