为什么7x7的深度卷积可以分解成3x3和1x11和11x1的深度卷积？

[EchoXu98]

您好！我想请问下，就是我标题中的问题“为什么7x7的深度卷积可以分解成3x3和1x11和11x1的深度卷积？” 这种分解是有严格数学推导吗？可以推导出分解前和分解后，二者的卷积核大小相同？还是因为效果好才这样分解？If you don't understand my question, I can ask it in English！

[yuweihao]

Hi @EchoXu98 ,

Thanks for your attention. "decompose" here is more like "replace" from the aspect of performance. Depthwise convolution and inception depthwise convolution are not mathematically equivalent.

[sdu-huanhq]

您好，请问Inception dep. conv中的参数量(2k=9)C/8是怎么计算出来的？Inception dep conv的参数量应该和g的设置有关系吧。
Hello, may I ask how to calculate the parameter number (2k=9)C/8 in Inception dep. conv?

[yuweihao]

Hi @sdu-huanhq ,

Thanks for your attention. Yes, g is set as 1/8 by default in Table 1. Thanks for your reminder, I will add this information in the table caption in the next revision.

[sdu-huanhq]

Hi @sdu-huanhq ,

Thanks for your attention. Yes, g is set as 1/8 by default in Table 1. Thanks for your reminder, I will add this information in the table caption in the next revision.

Thanks for your answer and thumbs up for your work

[yuweihao]

Thanks for your answer and thumbs up for your work

Thank you so much!

[116022017144]

您好，请问Inception dep. conv中的参数量(2k=9)C/8是怎么计算出来的？Inception dep conv的参数量应该和g的设置有关系吧。 Hello, may I ask how to calculate the parameter number (2k=9)C/8 in Inception dep. conv?

I want to know where is the (2k+9) from?I know the C/8 is the parallel channel count

[yuweihao]

您好，请问Inception dep. conv中的参数量(2k=9)C/8是怎么计算出来的？Inception dep conv的参数量应该和g的设置有关系吧。 Hello, may I ask how to calculate the parameter number (2k=9)C/8 in Inception dep. conv?

I want to know where is the (2k+9) from?I know the C/8 is the parallel channel count

2k from 1xk conv and kx1 conv and 9 from 3x3 conv.

[116022017144]

oh，I know it.thank you

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---原始邮件--- 发件人: "Weihao ***@***.***> 发送时间: 2023年5月8日(周一) 晚上9:32 收件人: ***@***.***>; 抄送: ***@***.******@***.***>; 主题: Re: [sail-sg/inceptionnext] 为什么7x7的深度卷积可以分解成3x3和1x11和11x1的深度卷积？ (Issue #3) 您好，请问Inception dep. conv中的参数量(2k=9)C/8是怎么计算出来的？Inception dep conv的参数量应该和g的设置有关系吧。 Hello, may I ask how to calculate the parameter number (2k=9)C/8 in Inception dep. conv? I want to know where is the (2k+9) from?I know the C/8 is the parallel channel count 2k from 1xk conv and kx1 conv and 9 from 3x3 conv. — Reply to this email directly, view it on GitHub, or unsubscribe. You are receiving this because you commented.Message ID: ***@***.***>