The porject is to find the path from the init position to the goal position. It contains the following steps: *
The code is showing as below:
# Define a function, search() that returns a list
# in the form of [optimal path length, row, col]. For
# the grid shown below, your function should output
# [11, 4, 5].
#
# If there is no valid path from the start point
# to the goal, your function should return the string
# 'fail'
# ----------
# Grid format:
# 0 = Navigable space
# 1 = Occupied space
grid = [[0, 0, 1, 0, 0, 0],
[0, 0, 1, 0, 0, 0],
[0, 0, 0, 0, 1, 0],
[0, 0, 1, 1, 1, 0],
[0, 0, 0, 0, 1, 0]]
init = [0, 0]
goal = [len(grid)-1, len(grid[0])-1]
cost = 1
delta = [[-1, 0], # go up
[ 0,-1], # go left
[ 1, 0], # go down
[ 0, 1]] # go right
delta_name = ['^', '<', 'v', '>']
def search(grid,init,goal,cost):
#Init the varialbles will be used
closed = [[0 for row in range(len(grid[0]))] for col in range(len(grid[1]))]
closed[init[0]][init[1]] = 1
x = init[0]
y = init[1]
g = 0
open = [[g,x,y]]
found = False
resign = False
while found is False and resign is False:
if (len(open) == 0):
resign = True
print("Failed")
else:
open.sort()
open.reverse()
next = open.pop()
g = next[0]
x = next[1]
y = next[2]
if x == goal[0] and y == goal[1]:
found = True
print(next)
else:
for i in range(len(delta)):
x2 = x + delta[i][0]
y2 = y + delta[i][1]
if x2 >= 0 and x2 < len(grid) and y2 >=0 and y2 < len(grid[0]):
if closed[x2][y2] == 0 and grid[x2][y2] == 0:
g2 = g + cost
open.append([g2,x2,y2])
closed[x2][y2] = 1
search(grid,init,goal,cost)