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Return promise from uiViewScroll #1702

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mikef438 opened this issue Jan 22, 2015 · 2 comments · Fixed by #1703
Closed

Return promise from uiViewScroll #1702

mikef438 opened this issue Jan 22, 2015 · 2 comments · Fixed by #1703
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feature
Milestone
0.2.14

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@mikef438
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I'm asking for the uiViewScroll function to return the timeout promise so that additional processing can occur once that is complete. The use case I have is with an iOS 7 bug on iPads that cause the screen to be blank until it's moved. In order to fix this I need to wait until the scroll completes and then move the screen an additional one pixel to make the content appear. For the time being I've had to use the source code from uiViewScroll and make my own function. Thanks!

Usage after issue resolved:
$uiViewScroll(element).then(function() { $window.scrollTo(0,1);});
@christopherthielen
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Seems fine, can you make a PR according to the contributor guidelines?

@christopherthielen christopherthielen added this to the 0.2.14 milestone Jan 22, 2015
@mikef438
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Sure

On Thursday, January 22, 2015, Chris Thielen notifications@github.com
wrote:

Seems fine, can you make a PR according to the contributor guidelines?

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Reply to this email directly or view it on GitHub
#1702 (comment)
.

Mike

mikef438 added a commit to mikef438/ui-router that referenced this issue Jan 22, 2015
@mikef438
feat($uiViewScroll): change function to return promise
c2a9a31 
return the promise from the timeout for additional processing

Closes angular-ui#1702
@mikef438 mikef438 mentioned this issue Jan 22, 2015
Merged
christopherthielen pushed a commit that referenced this issue Jul 11, 2015
@mikef438 @christopherthielen
feat($uiViewScroll): change function to return promise
fd992fc 
return the promise from the timeout for additional processing

Closes #1702
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feat($uiViewScroll): change function to return promise mikef438/ui-router
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@christopherthielen @mikef438